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6(x+3)=4(2x+9)+4x
We move all terms to the left:
6(x+3)-(4(2x+9)+4x)=0
We multiply parentheses
6x-(4(2x+9)+4x)+18=0
We calculate terms in parentheses: -(4(2x+9)+4x), so:We get rid of parentheses
4(2x+9)+4x
We add all the numbers together, and all the variables
4x+4(2x+9)
We multiply parentheses
4x+8x+36
We add all the numbers together, and all the variables
12x+36
Back to the equation:
-(12x+36)
6x-12x-36+18=0
We add all the numbers together, and all the variables
-6x-18=0
We move all terms containing x to the left, all other terms to the right
-6x=18
x=18/-6
x=-3
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