6(x+3)=42+4x

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Solution for 6(x+3)=42+4x equation: 



6(x+3)=42+4x

We move all terms to the left:

6(x+3)-(42+4x)=0

We add all the numbers together, and all the variables

6(x+3)-(4x+42)=0

We multiply parentheses

6x-(4x+42)+18=0

We get rid of parentheses

6x-4x-42+18=0

We add all the numbers together, and all the variables

2x-24=0

We move all terms containing x to the left, all other terms to the right

2x=24

x=24/2

x=12

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