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6(x+3)x=6x+3+15
We move all terms to the left:
6(x+3)x-(6x+3+15)=0
We add all the numbers together, and all the variables
6(x+3)x-(6x+18)=0
We multiply parentheses
6x^2+18x-(6x+18)=0
We get rid of parentheses
6x^2+18x-6x-18=0
We add all the numbers together, and all the variables
6x^2+12x-18=0
a = 6; b = 12; c = -18;
Δ = b2-4ac
Δ = 122-4·6·(-18)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-24}{2*6}=\frac{-36}{12} =-3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+24}{2*6}=\frac{12}{12} =1 $
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