6(x+4)+2=-11(x-5)-6

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Solution for 6(x+4)+2=-11(x-5)-6 equation: 



6(x+4)+2=-11(x-5)-6

We move all terms to the left:

6(x+4)+2-(-11(x-5)-6)=0

We multiply parentheses

6x-(-11(x-5)-6)+24+2=0



We calculate terms in parentheses: -(-11(x-5)-6), so:

-11(x-5)-6

We multiply parentheses

-11x+55-6

We add all the numbers together, and all the variables

-11x+49

Back to the equation:

-(-11x+49)



We add all the numbers together, and all the variables

6x-(-11x+49)+26=0

We get rid of parentheses

6x+11x-49+26=0

We add all the numbers together, and all the variables

17x-23=0

We move all terms containing x to the left, all other terms to the right

17x=23

x=23/17

x=1+6/17

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