6(x+4)+3(x-8)+7=2(x-5)+13

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Solution for 6(x+4)+3(x-8)+7=2(x-5)+13 equation: 



6(x+4)+3(x-8)+7=2(x-5)+13

We move all terms to the left:

6(x+4)+3(x-8)+7-(2(x-5)+13)=0

We multiply parentheses

6x+3x-(2(x-5)+13)+24-24+7=0



We calculate terms in parentheses: -(2(x-5)+13), so:

2(x-5)+13

We multiply parentheses

2x-10+13

We add all the numbers together, and all the variables

2x+3

Back to the equation:

-(2x+3)



We add all the numbers together, and all the variables

9x-(2x+3)+7=0

We get rid of parentheses

9x-2x-3+7=0

We add all the numbers together, and all the variables

7x+4=0

We move all terms containing x to the left, all other terms to the right

7x=-4

x=-4/7

x=-4/7

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