6(x+4)+8=11x-5(x-4)

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Solution for 6(x+4)+8=11x-5(x-4) equation:


Simplifying
6(x + 4) + 8 = 11x + -5(x + -4)

Reorder the terms:
6(4 + x) + 8 = 11x + -5(x + -4)
(4 * 6 + x * 6) + 8 = 11x + -5(x + -4)
(24 + 6x) + 8 = 11x + -5(x + -4)

Reorder the terms:
24 + 8 + 6x = 11x + -5(x + -4)

Combine like terms: 24 + 8 = 32
32 + 6x = 11x + -5(x + -4)

Reorder the terms:
32 + 6x = 11x + -5(-4 + x)
32 + 6x = 11x + (-4 * -5 + x * -5)
32 + 6x = 11x + (20 + -5x)

Reorder the terms:
32 + 6x = 20 + 11x + -5x

Combine like terms: 11x + -5x = 6x
32 + 6x = 20 + 6x

Add '-6x' to each side of the equation.
32 + 6x + -6x = 20 + 6x + -6x

Combine like terms: 6x + -6x = 0
32 + 0 = 20 + 6x + -6x
32 = 20 + 6x + -6x

Combine like terms: 6x + -6x = 0
32 = 20 + 0
32 = 20

Solving
32 = 20

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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