6(x+4)+x=4(x+3)+2

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Solution for 6(x+4)+x=4(x+3)+2 equation:



6(x+4)+x=4(x+3)+2
We move all terms to the left:
6(x+4)+x-(4(x+3)+2)=0
We add all the numbers together, and all the variables
x+6(x+4)-(4(x+3)+2)=0
We multiply parentheses
x+6x-(4(x+3)+2)+24=0
We calculate terms in parentheses: -(4(x+3)+2), so:
4(x+3)+2
We multiply parentheses
4x+12+2
We add all the numbers together, and all the variables
4x+14
Back to the equation:
-(4x+14)
We add all the numbers together, and all the variables
7x-(4x+14)+24=0
We get rid of parentheses
7x-4x-14+24=0
We add all the numbers together, and all the variables
3x+10=0
We move all terms containing x to the left, all other terms to the right
3x=-10
x=-10/3
x=-3+1/3

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