6(x+4)+x=4(x+4)+6

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Solution for 6(x+4)+x=4(x+4)+6 equation: 



6(x+4)+x=4(x+4)+6

We move all terms to the left:

6(x+4)+x-(4(x+4)+6)=0

We add all the numbers together, and all the variables

x+6(x+4)-(4(x+4)+6)=0

We multiply parentheses

x+6x-(4(x+4)+6)+24=0



We calculate terms in parentheses: -(4(x+4)+6), so:

4(x+4)+6

We multiply parentheses

4x+16+6

We add all the numbers together, and all the variables

4x+22

Back to the equation:

-(4x+22)



We add all the numbers together, and all the variables

7x-(4x+22)+24=0

We get rid of parentheses

7x-4x-22+24=0

We add all the numbers together, and all the variables

3x+2=0

We move all terms containing x to the left, all other terms to the right

3x=-2

x=-2/3

x=-2/3

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