6(x+4)=2(4x-3)

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Solution for 6(x+4)=2(4x-3) equation: 



6(x+4)=2(4x-3)

We move all terms to the left:

6(x+4)-(2(4x-3))=0

We multiply parentheses

6x-(2(4x-3))+24=0



We calculate terms in parentheses: -(2(4x-3)), so:

2(4x-3)

We multiply parentheses

8x-6

Back to the equation:

-(8x-6)



We get rid of parentheses

6x-8x+6+24=0

We add all the numbers together, and all the variables

-2x+30=0

We move all terms containing x to the left, all other terms to the right

-2x=-30

x=-30/-2

x=+15

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