6(x+5)+3=-6(x-4)-2

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Solution for 6(x+5)+3=-6(x-4)-2 equation: 



6(x+5)+3=-6(x-4)-2

We move all terms to the left:

6(x+5)+3-(-6(x-4)-2)=0

We multiply parentheses

6x-(-6(x-4)-2)+30+3=0



We calculate terms in parentheses: -(-6(x-4)-2), so:

-6(x-4)-2

We multiply parentheses

-6x+24-2

We add all the numbers together, and all the variables

-6x+22

Back to the equation:

-(-6x+22)



We add all the numbers together, and all the variables

6x-(-6x+22)+33=0

We get rid of parentheses

6x+6x-22+33=0

We add all the numbers together, and all the variables

12x+11=0

We move all terms containing x to the left, all other terms to the right

12x=-11

x=-11/12

x=-11/12

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