6(x+5)=2(3x+1)+28

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Solution for 6(x+5)=2(3x+1)+28 equation: 


Simplifying
6(x + 5) = 2(3x + 1) + 28

Reorder the terms:
6(5 + x) = 2(3x + 1) + 28
(5 * 6 + x * 6) = 2(3x + 1) + 28
(30 + 6x) = 2(3x + 1) + 28

Reorder the terms:
30 + 6x = 2(1 + 3x) + 28
30 + 6x = (1 * 2 + 3x * 2) + 28
30 + 6x = (2 + 6x) + 28

Reorder the terms:
30 + 6x = 2 + 28 + 6x

Combine like terms: 2 + 28 = 30
30 + 6x = 30 + 6x

Add '-30' to each side of the equation.
30 + -30 + 6x = 30 + -30 + 6x

Combine like terms: 30 + -30 = 0
0 + 6x = 30 + -30 + 6x
6x = 30 + -30 + 6x

Combine like terms: 30 + -30 = 0
6x = 0 + 6x
6x = 6x

Add '-6x' to each side of the equation.
6x + -6x = 6x + -6x

Combine like terms: 6x + -6x = 0
0 = 6x + -6x

Combine like terms: 6x + -6x = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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