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6(x+5)=5(x+2)
We move all terms to the left:
6(x+5)-(5(x+2))=0
We multiply parentheses
6x-(5(x+2))+30=0
We calculate terms in parentheses: -(5(x+2)), so:We get rid of parentheses
5(x+2)
We multiply parentheses
5x+10
Back to the equation:
-(5x+10)
6x-5x-10+30=0
We add all the numbers together, and all the variables
x+20=0
We move all terms containing x to the left, all other terms to the right
x=-20
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