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6(x+8)+3=-9(x-5)-5
We move all terms to the left:
6(x+8)+3-(-9(x-5)-5)=0
We multiply parentheses
6x-(-9(x-5)-5)+48+3=0
We calculate terms in parentheses: -(-9(x-5)-5), so:We add all the numbers together, and all the variables
-9(x-5)-5
We multiply parentheses
-9x+45-5
We add all the numbers together, and all the variables
-9x+40
Back to the equation:
-(-9x+40)
6x-(-9x+40)+51=0
We get rid of parentheses
6x+9x-40+51=0
We add all the numbers together, and all the variables
15x+11=0
We move all terms containing x to the left, all other terms to the right
15x=-11
x=-11/15
x=-11/15
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