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6(x+8)+5=2(2x-5)+x
We move all terms to the left:
6(x+8)+5-(2(2x-5)+x)=0
We multiply parentheses
6x-(2(2x-5)+x)+48+5=0
We calculate terms in parentheses: -(2(2x-5)+x), so:We add all the numbers together, and all the variables
2(2x-5)+x
We add all the numbers together, and all the variables
x+2(2x-5)
We multiply parentheses
x+4x-10
We add all the numbers together, and all the variables
5x-10
Back to the equation:
-(5x-10)
6x-(5x-10)+53=0
We get rid of parentheses
6x-5x+10+53=0
We add all the numbers together, and all the variables
x+63=0
We move all terms containing x to the left, all other terms to the right
x=-63
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