6(x-1)+1=3(x+1)-8,x

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Solution for 6(x-1)+1=3(x+1)-8,x equation: 



6(x-1)+1=3(x+1)-8.x

We move all terms to the left:

6(x-1)+1-(3(x+1)-8.x)=0

We multiply parentheses

6x-(3(x+1)-8.x)-6+1=0



We calculate terms in parentheses: -(3(x+1)-8.x), so:

3(x+1)-8.x

We add all the numbers together, and all the variables

-8x+3(x+1)

We multiply parentheses

-8x+3x+3

We add all the numbers together, and all the variables

-5x+3

Back to the equation:

-(-5x+3)



We add all the numbers together, and all the variables

6x-(-5x+3)-5=0

We get rid of parentheses

6x+5x-3-5=0

We add all the numbers together, and all the variables

11x-8=0

We move all terms containing x to the left, all other terms to the right

11x=8

x=8/11

x=8/11

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