6(x-1)+1=3(x+1)-8,x

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Solution for 6(x-1)+1=3(x+1)-8,x equation:



6(x-1)+1=3(x+1)-8.x
We move all terms to the left:
6(x-1)+1-(3(x+1)-8.x)=0
We multiply parentheses
6x-(3(x+1)-8.x)-6+1=0
We calculate terms in parentheses: -(3(x+1)-8.x), so:
3(x+1)-8.x
We add all the numbers together, and all the variables
-8x+3(x+1)
We multiply parentheses
-8x+3x+3
We add all the numbers together, and all the variables
-5x+3
Back to the equation:
-(-5x+3)
We add all the numbers together, and all the variables
6x-(-5x+3)-5=0
We get rid of parentheses
6x+5x-3-5=0
We add all the numbers together, and all the variables
11x-8=0
We move all terms containing x to the left, all other terms to the right
11x=8
x=8/11
x=8/11

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