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6(x-1)+1=3x+3(-1+x)
We move all terms to the left:
6(x-1)+1-(3x+3(-1+x))=0
We add all the numbers together, and all the variables
6(x-1)-(3x+3(x-1))+1=0
We multiply parentheses
6x-(3x+3(x-1))-6+1=0
We calculate terms in parentheses: -(3x+3(x-1)), so:We add all the numbers together, and all the variables
3x+3(x-1)
We multiply parentheses
3x+3x-3
We add all the numbers together, and all the variables
6x-3
Back to the equation:
-(6x-3)
6x-(6x-3)-5=0
We get rid of parentheses
6x-6x+3-5=0
We add all the numbers together, and all the variables
-2!=0
There is no solution for this equation
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