6(x-1)+1=4x-3(2-x)

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Solution for 6(x-1)+1=4x-3(2-x) equation: 



6(x-1)+1=4x-3(2-x)

We move all terms to the left:

6(x-1)+1-(4x-3(2-x))=0

We add all the numbers together, and all the variables

6(x-1)-(4x-3(-1x+2))+1=0

We multiply parentheses

6x-(4x-3(-1x+2))-6+1=0



We calculate terms in parentheses: -(4x-3(-1x+2)), so:

4x-3(-1x+2)

We multiply parentheses

4x+3x-6

We add all the numbers together, and all the variables

7x-6

Back to the equation:

-(7x-6)



We add all the numbers together, and all the variables

6x-(7x-6)-5=0

We get rid of parentheses

6x-7x+6-5=0

We add all the numbers together, and all the variables

-1x+1=0

We move all terms containing x to the left, all other terms to the right

-x=-1

x=-1/-1

x=1

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