6(x-1)+2(x-5)=28

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Solution for 6(x-1)+2(x-5)=28 equation: 



6(x-1)+2(x-5)=28

We move all terms to the left:

6(x-1)+2(x-5)-(28)=0

We multiply parentheses

6x+2x-6-10-28=0

We add all the numbers together, and all the variables

8x-44=0

We move all terms containing x to the left, all other terms to the right

8x=44

x=44/8

x=5+1/2

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