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6(x-1)+5x=3(10+3x)
We move all terms to the left:
6(x-1)+5x-(3(10+3x))=0
We add all the numbers together, and all the variables
6(x-1)+5x-(3(3x+10))=0
We add all the numbers together, and all the variables
5x+6(x-1)-(3(3x+10))=0
We multiply parentheses
5x+6x-(3(3x+10))-6=0
We calculate terms in parentheses: -(3(3x+10)), so:We add all the numbers together, and all the variables
3(3x+10)
We multiply parentheses
9x+30
Back to the equation:
-(9x+30)
11x-(9x+30)-6=0
We get rid of parentheses
11x-9x-30-6=0
We add all the numbers together, and all the variables
2x-36=0
We move all terms containing x to the left, all other terms to the right
2x=36
x=36/2
x=18
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