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6(x-1)-5=2x+4(-4+x)
We move all terms to the left:
6(x-1)-5-(2x+4(-4+x))=0
We add all the numbers together, and all the variables
6(x-1)-(2x+4(x-4))-5=0
We multiply parentheses
6x-(2x+4(x-4))-6-5=0
We calculate terms in parentheses: -(2x+4(x-4)), so:We add all the numbers together, and all the variables
2x+4(x-4)
We multiply parentheses
2x+4x-16
We add all the numbers together, and all the variables
6x-16
Back to the equation:
-(6x-16)
6x-(6x-16)-11=0
We get rid of parentheses
6x-6x+16-11=0
We add all the numbers together, and all the variables
5!=0
There is no solution for this equation
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