6(x-1)-x=2(x+1)+x-1

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Solution for 6(x-1)-x=2(x+1)+x-1 equation: 



6(x-1)-x=2(x+1)+x-1

We move all terms to the left:

6(x-1)-x-(2(x+1)+x-1)=0

We add all the numbers together, and all the variables

-1x+6(x-1)-(2(x+1)+x-1)=0

We multiply parentheses

-1x+6x-(2(x+1)+x-1)-6=0



We calculate terms in parentheses: -(2(x+1)+x-1), so:

2(x+1)+x-1

We add all the numbers together, and all the variables

x+2(x+1)-1

We multiply parentheses

x+2x+2-1

We add all the numbers together, and all the variables

3x+1

Back to the equation:

-(3x+1)



We add all the numbers together, and all the variables

5x-(3x+1)-6=0

We get rid of parentheses

5x-3x-1-6=0

We add all the numbers together, and all the variables

2x-7=0

We move all terms containing x to the left, all other terms to the right

2x=7

x=7/2

x=3+1/2

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