6(x-1)-x=2(x+1)+x-1

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Solution for 6(x-1)-x=2(x+1)+x-1 equation:



6(x-1)-x=2(x+1)+x-1
We move all terms to the left:
6(x-1)-x-(2(x+1)+x-1)=0
We add all the numbers together, and all the variables
-1x+6(x-1)-(2(x+1)+x-1)=0
We multiply parentheses
-1x+6x-(2(x+1)+x-1)-6=0
We calculate terms in parentheses: -(2(x+1)+x-1), so:
2(x+1)+x-1
We add all the numbers together, and all the variables
x+2(x+1)-1
We multiply parentheses
x+2x+2-1
We add all the numbers together, and all the variables
3x+1
Back to the equation:
-(3x+1)
We add all the numbers together, and all the variables
5x-(3x+1)-6=0
We get rid of parentheses
5x-3x-1-6=0
We add all the numbers together, and all the variables
2x-7=0
We move all terms containing x to the left, all other terms to the right
2x=7
x=7/2
x=3+1/2

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