6(x-1)/2=3(x+2)/4

Solution for 6(x-1)/2=3(x+2)/4 equation:

6(x-1)/2=3(x+2)/4

We move all terms to the left:

6(x-1)/2-(3(x+2)/4)=0

We calculate fractions


6x/()+(-(3(x+2)*2)/()=0


We calculate terms in parentheses: +(-(3(x+2)*2)/(), so:

-(3(x+2)*2)/(

We multiply all the terms by the denominator


-(3(x+2)*2)


We calculate terms in parentheses: -(3(x+2)*2), so:

3(x+2)*2

We multiply parentheses

6x+12

Back to the equation:

-(6x+12)


We get rid of parentheses

-6x-12

Back to the equation:

+(-6x-12)


We get rid of parentheses

6x/()-6x-12=0

We multiply all the terms by the denominator


6x-6x*()-12*()=0

We add all the numbers together, and all the variables

6x-6x*()=0