6(x-1)/2=3(x+3)/5

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Solution for 6(x-1)/2=3(x+3)/5 equation:



6(x-1)/2=3(x+3)/5
We move all terms to the left:
6(x-1)/2-(3(x+3)/5)=0
We calculate fractions
6x/()+(-(3(x+3)*2)/()=0
We calculate terms in parentheses: +(-(3(x+3)*2)/(), so:
-(3(x+3)*2)/(
We multiply all the terms by the denominator
-(3(x+3)*2)
We calculate terms in parentheses: -(3(x+3)*2), so:
3(x+3)*2
We multiply parentheses
6x+18
Back to the equation:
-(6x+18)
We get rid of parentheses
-6x-18
Back to the equation:
+(-6x-18)
We get rid of parentheses
6x/()-6x-18=0
We multiply all the terms by the denominator
6x-6x*()-18*()=0
We add all the numbers together, and all the variables
6x-6x*()=0

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