6(x-1)/3=4(x-4)/12

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Solution for 6(x-1)/3=4(x-4)/12 equation: 



6(x-1)/3=4(x-4)/12

We move all terms to the left:

6(x-1)/3-(4(x-4)/12)=0

We calculate fractions


6x/()+(-(4(x-4)*3)/()=0



We calculate terms in parentheses: +(-(4(x-4)*3)/(), so:

-(4(x-4)*3)/(

We multiply all the terms by the denominator


-(4(x-4)*3)



We calculate terms in parentheses: -(4(x-4)*3), so:

4(x-4)*3

We multiply parentheses

12x-48

Back to the equation:

-(12x-48)



We get rid of parentheses

-12x+48

Back to the equation:

+(-12x+48)



We get rid of parentheses

6x/()-12x+48=0

We multiply all the terms by the denominator


6x-12x*()+48*()=0

We add all the numbers together, and all the variables

6x-12x*()=0

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