6(x-1)/8=3(x+1)/6

Solution for 6(x-1)/8=3(x+1)/6 equation:

6(x-1)/8=3(x+1)/6

We move all terms to the left:

6(x-1)/8-(3(x+1)/6)=0

We calculate fractions


6x/()+(-(3(x+1)*8)/()=0


We calculate terms in parentheses: +(-(3(x+1)*8)/(), so:

-(3(x+1)*8)/(

We multiply all the terms by the denominator


-(3(x+1)*8)


We calculate terms in parentheses: -(3(x+1)*8), so:

3(x+1)*8

We multiply parentheses

24x+24

Back to the equation:

-(24x+24)


We get rid of parentheses

-24x-24

Back to the equation:

+(-24x-24)


We get rid of parentheses

6x/()-24x-24=0

We multiply all the terms by the denominator


6x-24x*()-24*()=0

We add all the numbers together, and all the variables

6x-24x*()=0