6(x-1)/8=3(x+4)/9

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Solution for 6(x-1)/8=3(x+4)/9 equation: 



6(x-1)/8=3(x+4)/9

We move all terms to the left:

6(x-1)/8-(3(x+4)/9)=0

We calculate fractions


6x/()+(-(3(x+4)*8)/()=0



We calculate terms in parentheses: +(-(3(x+4)*8)/(), so:

-(3(x+4)*8)/(

We multiply all the terms by the denominator


-(3(x+4)*8)



We calculate terms in parentheses: -(3(x+4)*8), so:

3(x+4)*8

We multiply parentheses

24x+96

Back to the equation:

-(24x+96)



We get rid of parentheses

-24x-96

Back to the equation:

+(-24x-96)



We get rid of parentheses

6x/()-24x-96=0

We multiply all the terms by the denominator


6x-24x*()-96*()=0

We add all the numbers together, and all the variables

6x-24x*()=0

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