6(x-1)/9=2(x+1)/5

Solution for 6(x-1)/9=2(x+1)/5 equation:

6(x-1)/9=2(x+1)/5

We move all terms to the left:

6(x-1)/9-(2(x+1)/5)=0

We calculate fractions


6x/()+(-(2(x+1)*9)/()=0


We calculate terms in parentheses: +(-(2(x+1)*9)/(), so:

-(2(x+1)*9)/(

We multiply all the terms by the denominator


-(2(x+1)*9)


We calculate terms in parentheses: -(2(x+1)*9), so:

2(x+1)*9

We multiply parentheses

18x+18

Back to the equation:

-(18x+18)


We get rid of parentheses

-18x-18

Back to the equation:

+(-18x-18)


We get rid of parentheses

6x/()-18x-18=0

We multiply all the terms by the denominator


6x-18x*()-18*()=0

We add all the numbers together, and all the variables

6x-18x*()=0