6(x-1)=3(x+12)

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Solution for 6(x-1)=3(x+12) equation:



6(x-1)=3(x+12)
We move all terms to the left:
6(x-1)-(3(x+12))=0
We multiply parentheses
6x-(3(x+12))-6=0
We calculate terms in parentheses: -(3(x+12)), so:
3(x+12)
We multiply parentheses
3x+36
Back to the equation:
-(3x+36)
We get rid of parentheses
6x-3x-36-6=0
We add all the numbers together, and all the variables
3x-42=0
We move all terms containing x to the left, all other terms to the right
3x=42
x=42/3
x=14

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