6(x-1)=x2+10

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Solution for 6(x-1)=x2+10 equation: 



6(x-1)=x2+10

We move all terms to the left:

6(x-1)-(x2+10)=0

We add all the numbers together, and all the variables

-(+x^2+10)+6(x-1)=0

We multiply parentheses

-(+x^2+10)+6x-6=0

We get rid of parentheses

-x^2+6x-10-6=0

We add all the numbers together, and all the variables

-1x^2+6x-16=0

a = -1; b = 6; c = -16;
Δ = b2-4ac
Δ = 62-4·(-1)·(-16)
Δ = -28
Delta is less than zero, so there is no solution for the equation

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