6(x-12)=2(11x-4)

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Solution for 6(x-12)=2(11x-4) equation: 



6(x-12)=2(11x-4)

We move all terms to the left:

6(x-12)-(2(11x-4))=0

We multiply parentheses

6x-(2(11x-4))-72=0



We calculate terms in parentheses: -(2(11x-4)), so:

2(11x-4)

We multiply parentheses

22x-8

Back to the equation:

-(22x-8)



We get rid of parentheses

6x-22x+8-72=0

We add all the numbers together, and all the variables

-16x-64=0

We move all terms containing x to the left, all other terms to the right

-16x=64

x=64/-16

x=-4

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