6(x-2)+1=2(3x-5)

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Solution for 6(x-2)+1=2(3x-5) equation:


Simplifying
6(x + -2) + 1 = 2(3x + -5)

Reorder the terms:
6(-2 + x) + 1 = 2(3x + -5)
(-2 * 6 + x * 6) + 1 = 2(3x + -5)
(-12 + 6x) + 1 = 2(3x + -5)

Reorder the terms:
-12 + 1 + 6x = 2(3x + -5)

Combine like terms: -12 + 1 = -11
-11 + 6x = 2(3x + -5)

Reorder the terms:
-11 + 6x = 2(-5 + 3x)
-11 + 6x = (-5 * 2 + 3x * 2)
-11 + 6x = (-10 + 6x)

Add '-6x' to each side of the equation.
-11 + 6x + -6x = -10 + 6x + -6x

Combine like terms: 6x + -6x = 0
-11 + 0 = -10 + 6x + -6x
-11 = -10 + 6x + -6x

Combine like terms: 6x + -6x = 0
-11 = -10 + 0
-11 = -10

Solving
-11 = -10

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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