6(x-2)+3x=15-2(x+3)

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Solution for 6(x-2)+3x=15-2(x+3) equation: 



6(x-2)+3x=15-2(x+3)

We move all terms to the left:

6(x-2)+3x-(15-2(x+3))=0

We add all the numbers together, and all the variables

3x+6(x-2)-(15-2(x+3))=0

We multiply parentheses

3x+6x-(15-2(x+3))-12=0



We calculate terms in parentheses: -(15-2(x+3)), so:

15-2(x+3)

determiningTheFunctionDomain
-2(x+3)+15

We multiply parentheses

-2x-6+15

We add all the numbers together, and all the variables

-2x+9

Back to the equation:

-(-2x+9)



We add all the numbers together, and all the variables

9x-(-2x+9)-12=0

We get rid of parentheses

9x+2x-9-12=0

We add all the numbers together, and all the variables

11x-21=0

We move all terms containing x to the left, all other terms to the right

11x=21

x=21/11

x=1+10/11

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