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6(x-2)+3x=9(x+1)-3
We move all terms to the left:
6(x-2)+3x-(9(x+1)-3)=0
We add all the numbers together, and all the variables
3x+6(x-2)-(9(x+1)-3)=0
We multiply parentheses
3x+6x-(9(x+1)-3)-12=0
We calculate terms in parentheses: -(9(x+1)-3), so:We add all the numbers together, and all the variables
9(x+1)-3
We multiply parentheses
9x+9-3
We add all the numbers together, and all the variables
9x+6
Back to the equation:
-(9x+6)
9x-(9x+6)-12=0
We get rid of parentheses
9x-9x-6-12=0
We add all the numbers together, and all the variables
-18!=0
There is no solution for this equation
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