6(x-2)+3x=9(x+1)-3

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Solution for 6(x-2)+3x=9(x+1)-3 equation: 



6(x-2)+3x=9(x+1)-3

We move all terms to the left:

6(x-2)+3x-(9(x+1)-3)=0

We add all the numbers together, and all the variables

3x+6(x-2)-(9(x+1)-3)=0

We multiply parentheses

3x+6x-(9(x+1)-3)-12=0



We calculate terms in parentheses: -(9(x+1)-3), so:

9(x+1)-3

We multiply parentheses

9x+9-3

We add all the numbers together, and all the variables

9x+6

Back to the equation:

-(9x+6)



We add all the numbers together, and all the variables

9x-(9x+6)-12=0

We get rid of parentheses

9x-9x-6-12=0

We add all the numbers together, and all the variables

-18!=0

There is no solution for this equation

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