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6(x-2)+4=6(x+2)
We move all terms to the left:
6(x-2)+4-(6(x+2))=0
We multiply parentheses
6x-(6(x+2))-12+4=0
We calculate terms in parentheses: -(6(x+2)), so:We add all the numbers together, and all the variables
6(x+2)
We multiply parentheses
6x+12
Back to the equation:
-(6x+12)
6x-(6x+12)-8=0
We get rid of parentheses
6x-6x-12-8=0
We add all the numbers together, and all the variables
-20!=0
There is no solution for this equation
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