6(x-2)+4x=3(x+13)-2

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Solution for 6(x-2)+4x=3(x+13)-2 equation: 



6(x-2)+4x=3(x+13)-2

We move all terms to the left:

6(x-2)+4x-(3(x+13)-2)=0

We add all the numbers together, and all the variables

4x+6(x-2)-(3(x+13)-2)=0

We multiply parentheses

4x+6x-(3(x+13)-2)-12=0



We calculate terms in parentheses: -(3(x+13)-2), so:

3(x+13)-2

We multiply parentheses

3x+39-2

We add all the numbers together, and all the variables

3x+37

Back to the equation:

-(3x+37)



We add all the numbers together, and all the variables

10x-(3x+37)-12=0

We get rid of parentheses

10x-3x-37-12=0

We add all the numbers together, and all the variables

7x-49=0

We move all terms containing x to the left, all other terms to the right

7x=49

x=49/7

x=7

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