6(x-2)+7(x-3)=14

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Solution for 6(x-2)+7(x-3)=14 equation: 



6(x-2)+7(x-3)=14

We move all terms to the left:

6(x-2)+7(x-3)-(14)=0

We multiply parentheses

6x+7x-12-21-14=0

We add all the numbers together, and all the variables

13x-47=0

We move all terms containing x to the left, all other terms to the right

13x=47

x=47/13

x=3+8/13

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