6(x-2)-(3-2x)=3(x-4)

Solution for 6(x-2)-(3-2x)=3(x-4) equation:

6(x-2)-(3-2x)=3(x-4)

We move all terms to the left:

6(x-2)-(3-2x)-(3(x-4))=0

We add all the numbers together, and all the variables

6(x-2)-(-2x+3)-(3(x-4))=0

We multiply parentheses

6x-(-2x+3)-(3(x-4))-12=0

We get rid of parentheses

6x+2x-(3(x-4))-3-12=0


We calculate terms in parentheses: -(3(x-4)), so:

3(x-4)

We multiply parentheses

3x-12

Back to the equation:

-(3x-12)


We add all the numbers together, and all the variables

8x-(3x-12)-15=0

We get rid of parentheses

8x-3x+12-15=0

We add all the numbers together, and all the variables

5x-3=0

We move all terms containing x to the left, all other terms to the right

5x=3

x=3/5

x=3/5