6(x-2)-3(x+1)=2(x-1)+7

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Solution for 6(x-2)-3(x+1)=2(x-1)+7 equation: 



6(x-2)-3(x+1)=2(x-1)+7

We move all terms to the left:

6(x-2)-3(x+1)-(2(x-1)+7)=0

We multiply parentheses

6x-3x-(2(x-1)+7)-12-3=0



We calculate terms in parentheses: -(2(x-1)+7), so:

2(x-1)+7

We multiply parentheses

2x-2+7

We add all the numbers together, and all the variables

2x+5

Back to the equation:

-(2x+5)



We add all the numbers together, and all the variables

3x-(2x+5)-15=0

We get rid of parentheses

3x-2x-5-15=0

We add all the numbers together, and all the variables

x-20=0

We move all terms containing x to the left, all other terms to the right

x=20

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