6(x-2)-3(x-4)=3(x+6)

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Solution for 6(x-2)-3(x-4)=3(x+6) equation:


Simplifying
6(x + -2) + -3(x + -4) = 3(x + 6)

Reorder the terms:
6(-2 + x) + -3(x + -4) = 3(x + 6)
(-2 * 6 + x * 6) + -3(x + -4) = 3(x + 6)
(-12 + 6x) + -3(x + -4) = 3(x + 6)

Reorder the terms:
-12 + 6x + -3(-4 + x) = 3(x + 6)
-12 + 6x + (-4 * -3 + x * -3) = 3(x + 6)
-12 + 6x + (12 + -3x) = 3(x + 6)

Reorder the terms:
-12 + 12 + 6x + -3x = 3(x + 6)

Combine like terms: -12 + 12 = 0
0 + 6x + -3x = 3(x + 6)
6x + -3x = 3(x + 6)

Combine like terms: 6x + -3x = 3x
3x = 3(x + 6)

Reorder the terms:
3x = 3(6 + x)
3x = (6 * 3 + x * 3)
3x = (18 + 3x)

Add '-3x' to each side of the equation.
3x + -3x = 18 + 3x + -3x

Combine like terms: 3x + -3x = 0
0 = 18 + 3x + -3x

Combine like terms: 3x + -3x = 0
0 = 18 + 0
0 = 18

Solving
0 = 18

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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