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6(x-2)-3=2x+4(-5+x)
We move all terms to the left:
6(x-2)-3-(2x+4(-5+x))=0
We add all the numbers together, and all the variables
6(x-2)-(2x+4(x-5))-3=0
We multiply parentheses
6x-(2x+4(x-5))-12-3=0
We calculate terms in parentheses: -(2x+4(x-5)), so:We add all the numbers together, and all the variables
2x+4(x-5)
We multiply parentheses
2x+4x-20
We add all the numbers together, and all the variables
6x-20
Back to the equation:
-(6x-20)
6x-(6x-20)-15=0
We get rid of parentheses
6x-6x+20-15=0
We add all the numbers together, and all the variables
5!=0
There is no solution for this equation
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