6(x-2)-4(x-3)=4(x+4)-(x-9)

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Solution for 6(x-2)-4(x-3)=4(x+4)-(x-9) equation: 



6(x-2)-4(x-3)=4(x+4)-(x-9)

We move all terms to the left:

6(x-2)-4(x-3)-(4(x+4)-(x-9))=0

We multiply parentheses

6x-4x-(4(x+4)-(x-9))-12+12=0



We calculate terms in parentheses: -(4(x+4)-(x-9)), so:

4(x+4)-(x-9)

We multiply parentheses

4x-(x-9)+16

We get rid of parentheses

4x-x+9+16

We add all the numbers together, and all the variables

3x+25

Back to the equation:

-(3x+25)



We add all the numbers together, and all the variables

2x-(3x+25)=0

We get rid of parentheses

2x-3x-25=0

We add all the numbers together, and all the variables

-1x-25=0

We move all terms containing x to the left, all other terms to the right

-x=25

x=25/-1

x=-25

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