6(x-2)-5(3x+4)=x-32

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Solution for 6(x-2)-5(3x+4)=x-32 equation: 



6(x-2)-5(3x+4)=x-32

We move all terms to the left:

6(x-2)-5(3x+4)-(x-32)=0

We multiply parentheses

6x-15x-(x-32)-12-20=0

We get rid of parentheses

6x-15x-x+32-12-20=0

We add all the numbers together, and all the variables

-10x=0

x=0/-10

x=0

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