6(x-2)-8=-7(-3x+4)-5x

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Solution for 6(x-2)-8=-7(-3x+4)-5x equation: 



6(x-2)-8=-7(-3x+4)-5x

We move all terms to the left:

6(x-2)-8-(-7(-3x+4)-5x)=0

We multiply parentheses

6x-(-7(-3x+4)-5x)-12-8=0



We calculate terms in parentheses: -(-7(-3x+4)-5x), so:

-7(-3x+4)-5x

We add all the numbers together, and all the variables

-5x-7(-3x+4)

We multiply parentheses

-5x+21x-28

We add all the numbers together, and all the variables

16x-28

Back to the equation:

-(16x-28)



We add all the numbers together, and all the variables

6x-(16x-28)-20=0

We get rid of parentheses

6x-16x+28-20=0

We add all the numbers together, and all the variables

-10x+8=0

We move all terms containing x to the left, all other terms to the right

-10x=-8

x=-8/-10

x=4/5

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