6(x-2)-x=-1-3(x-4)

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Solution for 6(x-2)-x=-1-3(x-4) equation: 



6(x-2)-x=-1-3(x-4)

We move all terms to the left:

6(x-2)-x-(-1-3(x-4))=0

We add all the numbers together, and all the variables

-1x+6(x-2)-(-1-3(x-4))=0

We multiply parentheses

-1x+6x-(-1-3(x-4))-12=0



We calculate terms in parentheses: -(-1-3(x-4)), so:

-1-3(x-4)

determiningTheFunctionDomain
-3(x-4)-1

We multiply parentheses

-3x+12-1

We add all the numbers together, and all the variables

-3x+11

Back to the equation:

-(-3x+11)



We add all the numbers together, and all the variables

5x-(-3x+11)-12=0

We get rid of parentheses

5x+3x-11-12=0

We add all the numbers together, and all the variables

8x-23=0

We move all terms containing x to the left, all other terms to the right

8x=23

x=23/8

x=2+7/8

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