6(x-2)-x=3+2(2x+1)

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Solution for 6(x-2)-x=3+2(2x+1) equation: 



6(x-2)-x=3+2(2x+1)

We move all terms to the left:

6(x-2)-x-(3+2(2x+1))=0

We add all the numbers together, and all the variables

-1x+6(x-2)-(3+2(2x+1))=0

We multiply parentheses

-1x+6x-(3+2(2x+1))-12=0



We calculate terms in parentheses: -(3+2(2x+1)), so:

3+2(2x+1)

determiningTheFunctionDomain
2(2x+1)+3

We multiply parentheses

4x+2+3

We add all the numbers together, and all the variables

4x+5

Back to the equation:

-(4x+5)



We add all the numbers together, and all the variables

5x-(4x+5)-12=0

We get rid of parentheses

5x-4x-5-12=0

We add all the numbers together, and all the variables

x-17=0

We move all terms containing x to the left, all other terms to the right

x=17

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