6(x-2)/12=2(x+2)/8

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Solution for 6(x-2)/12=2(x+2)/8 equation: 



6(x-2)/12=2(x+2)/8

We move all terms to the left:

6(x-2)/12-(2(x+2)/8)=0

We calculate fractions


6x/()+(-(2(x+2)*12)/()=0



We calculate terms in parentheses: +(-(2(x+2)*12)/(), so:

-(2(x+2)*12)/(

We multiply all the terms by the denominator


-(2(x+2)*12)



We calculate terms in parentheses: -(2(x+2)*12), so:

2(x+2)*12

We multiply parentheses

24x+48

Back to the equation:

-(24x+48)



We get rid of parentheses

-24x-48

Back to the equation:

+(-24x-48)



We get rid of parentheses

6x/()-24x-48=0

We multiply all the terms by the denominator


6x-24x*()-48*()=0

We add all the numbers together, and all the variables

6x-24x*()=0

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