6(x-2)/12=2(x+4)/10

Solution for 6(x-2)/12=2(x+4)/10 equation:

6(x-2)/12=2(x+4)/10

We move all terms to the left:

6(x-2)/12-(2(x+4)/10)=0

We calculate fractions


6x/()+(-(2(x+4)*12)/()=0


We calculate terms in parentheses: +(-(2(x+4)*12)/(), so:

-(2(x+4)*12)/(

We multiply all the terms by the denominator


-(2(x+4)*12)


We calculate terms in parentheses: -(2(x+4)*12), so:

2(x+4)*12

We multiply parentheses

24x+96

Back to the equation:

-(24x+96)


We get rid of parentheses

-24x-96

Back to the equation:

+(-24x-96)


We get rid of parentheses

6x/()-24x-96=0

We multiply all the terms by the denominator


6x-24x*()-96*()=0

We add all the numbers together, and all the variables

6x-24x*()=0