6(x-2)/2=2(x+4)/7

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Solution for 6(x-2)/2=2(x+4)/7 equation: 



6(x-2)/2=2(x+4)/7

We move all terms to the left:

6(x-2)/2-(2(x+4)/7)=0

We calculate fractions


6x/()+(-(2(x+4)*2)/()=0



We calculate terms in parentheses: +(-(2(x+4)*2)/(), so:

-(2(x+4)*2)/(

We multiply all the terms by the denominator


-(2(x+4)*2)



We calculate terms in parentheses: -(2(x+4)*2), so:

2(x+4)*2

We multiply parentheses

4x+16

Back to the equation:

-(4x+16)



We get rid of parentheses

-4x-16

Back to the equation:

+(-4x-16)



We get rid of parentheses

6x/()-4x-16=0

We multiply all the terms by the denominator


6x-4x*()-16*()=0

We add all the numbers together, and all the variables

6x-4x*()=0

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