6(x-2)/2=6(x+1)/8

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Solution for 6(x-2)/2=6(x+1)/8 equation:



6(x-2)/2=6(x+1)/8
We move all terms to the left:
6(x-2)/2-(6(x+1)/8)=0
We calculate fractions
6x/()+(-(6(x+1)*2)/()=0
We calculate terms in parentheses: +(-(6(x+1)*2)/(), so:
-(6(x+1)*2)/(
We multiply all the terms by the denominator
-(6(x+1)*2)
We calculate terms in parentheses: -(6(x+1)*2), so:
6(x+1)*2
We multiply parentheses
12x+12
Back to the equation:
-(12x+12)
We get rid of parentheses
-12x-12
Back to the equation:
+(-12x-12)
We get rid of parentheses
6x/()-12x-12=0
We multiply all the terms by the denominator
6x-12x*()-12*()=0
We add all the numbers together, and all the variables
6x-12x*()=0

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