6(x-2)/3=2(x+3)/6

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Solution for 6(x-2)/3=2(x+3)/6 equation:



6(x-2)/3=2(x+3)/6
We move all terms to the left:
6(x-2)/3-(2(x+3)/6)=0
We calculate fractions
6x/()+(-(2(x+3)*3)/()=0
We calculate terms in parentheses: +(-(2(x+3)*3)/(), so:
-(2(x+3)*3)/(
We multiply all the terms by the denominator
-(2(x+3)*3)
We calculate terms in parentheses: -(2(x+3)*3), so:
2(x+3)*3
We multiply parentheses
6x+18
Back to the equation:
-(6x+18)
We get rid of parentheses
-6x-18
Back to the equation:
+(-6x-18)
We get rid of parentheses
6x/()-6x-18=0
We multiply all the terms by the denominator
6x-6x*()-18*()=0
We add all the numbers together, and all the variables
6x-6x*()=0

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